Compare Version Numbers

Source

• leetcode: Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

java

public class Solution {
    public int compareVersion(String version1, String version2) {
        String[] v1 = version1.split("\\.");
        String[] v2 = version2.split("\\.");

        int length = Math.max(v1.length,v2.length);

        for(int i=0; i<length; i++){
            int ver1 = i<v1.length? Integer.parseInt(v1[i]): 0;
            int ver2 = i<v2.length? Integer.parseInt(v2[i]): 0;

            if(ver1>ver2) return 1;
            else if(ver1<ver2) return -1;
        }
        return 0;
    }
}